Sunday, August 2, 2009

C program....?

Write two versions of a program that displays the follwing table:





X X cubed


------------- -----------





Have the table continue until X is 20.





a. For the first version, write a function to do the cube calculation that takes


a single parameter. If the parameter is 2 on entry to the function, the parameter


should have the value 8 on exit from the function. That is, implement a


"pass by reference" on the function's parameter and have the cubed value


passed back in the parameter.





b. For the second version, write a function that does the cubing, but, have


the cubed value passed back to the main program as the return value of the function.

C program....?
JFalt's answer is right on, but it's C++ syntax, not C.





(I don' tmean to nitpick, but this is obviously important if you are trying to compile with a C compiler that doesn't understand C++).





#include %26lt;stdio.h%26gt;





void cubeByReference(int* val);


int cubeByValue(int val);





int main()


{


int initialValue = 2;


int val = cubeByValue(initialValue);


printf("cubeByValue of %d is %d\n", initialValue, val);





val = initialValue;


cubeByReference(%26amp;val);


printf("cubeByReference of %d is %d\n", initialValue, val);


}





int cubeByValue(int val)


{


return val * val * val;


}





void cubeByReference(int *val)


{


*val = (*val) * (*val) * (*val);


}





HTH-
Reply:#include %26lt;iostream%26gt;





using namespace std;





void cubeByReference(int* val);


int cubeByValue(int val);





int main()


{


int initialValue = 2;


int val = cubeByValue(initialValue);


cout %26lt;%26lt; "cubeByValue(" %26lt;%26lt; initialValue %26lt;%26lt;") = " %26lt;%26lt; val %26lt;%26lt; endl;





val = initialValue;


cubeByReference(%26amp;val);


cout %26lt;%26lt; "cubeByReference(" %26lt;%26lt; initialValue %26lt;%26lt;") = " %26lt;%26lt; val %26lt;%26lt; endl;


}


int cubeByValue(int val)


{


return val * val * val;


}


void cubeByReference(int *val)


{


*val = *val * *val * *val;


}
Reply:hehehe is this for your homework.. I wish I had this back when I was in school thats funny

dogwood

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