C++ challenging quetion about quotient?

State two ways to compute the approximate numerical value of the quotient a/b if a and b are both integer variables in a C++ program. (b !=0)


one way is certainly a=a/b;


What do u think is the other way???


maybe be using reference ? or other tricky way?

C++ challenging quetion about quotient?
c=0;


while (b%26gt;=a)


{


b=b-a;


c++;


}


cout%26lt;%26lt;c;





given b is the divident and a is the divisor, c is the quotient
Reply:you wana divide two integers ,





int a,b;


// short ways is below


a/=b;


// will be a = a/b ;








hey, your question is also confusing , you have not decalred what you want (exactly ) . . .





WELL JOHN , A CHANGE IN YOUR MIND WASN"T GOOD IDEA . . . all the best with your programming and make sure you don't mess up with the variable in your real program instead of c you use a ;-)





joking,





all the best








a l the best
Reply:%26gt;%26gt;one way is certainly a=a/b;


I don't think so.








If a=7 and b=3, then a/b will give you 2, not 2.3333 as you were expecting. That's because both are integers and


int / int will give you an int.





You will have to cast at least one of those integers to float like this:


(static_cast%26lt;float%26gt;a) / b;